Php rozdíl mezi dvěma daty v letech měsíců a dnů
Příklady kódu
php rozdíl mezi dvěma daty v letech měsíců a dnů
//get Date diff as intervals
$d1 = new DateTime("2018-01-10 00:00:00");
$d2 = new DateTime("2019-05-18 01:23:45");
$interval = $d1->diff($d2);
$diffInSeconds = $interval->s; //45
$diffInMinutes = $interval->i; //23
$diffInHours = $interval->h; //8
$diffInDays = $interval->d; //21
$diffInMonths = $interval->m; //4
$diffInYears = $interval->y; //1
//or get Date difference as total difference
$d1 = strtotime("2018-01-10 00:00:00");
$d2 = strtotime("2019-05-18 01:23:45");
$totalSecondsDiff = abs($d1-$d2); //42600225
$totalMinutesDiff = $totalSecondsDiff/60; //710003.75
$totalHoursDiff = $totalSecondsDiff/60/60;//11833.39
$totalDaysDiff = $totalSecondsDiff/60/60/24; //493.05
$totalMonthsDiff = $totalSecondsDiff/60/60/24/30; //16.43
$totalYearsDiff = $totalSecondsDiff/60/60/24/365; //1.35php výpočet rozdílu data
//get Date diff as intervals
$d1 = new DateTime("2018-01-10 00:00:00");
$d2 = new DateTime("2019-05-18 01:23:45");
$interval = $d1->diff($d2);
$diffInSeconds = $interval->s; //45
$diffInMinutes = $interval->i; //23
$diffInHours = $interval->h; //8
$diffInDays = $interval->d; //21
$diffInMonths = $interval->m; //4
$diffInYears = $interval->y; //1
//or get Date difference as total difference
$d1 = strtotime("2018-01-10 00:00:00");
$d2 = strtotime("2019-05-18 01:23:45");
$totalSecondsDiff = abs($d1-$d2); //42600225
$totalMinutesDiff = $totalSecondsDiff/60; //710003.75
$totalHoursDiff = $totalSecondsDiff/60/60;//11833.39
$totalDaysDiff = $totalSecondsDiff/60/60/24; //493.05
$totalMonthsDiff = $totalSecondsDiff/60/60/24/30; //16.43
$totalYearsDiff = $totalSecondsDiff/60/60/24/365; //1.35Získejte počet dní mezi dvěma daty v PHP
$startDate = new DateTime("2019-10-27");
$endDate = new DateTime("2020-04-11");
$difference = $endDate->diff($startDate);
echo $difference->format("%a");Vypočítejte rozdíl mezi dvěma daty pomocí PHP
phpCopy$firstDate = "2019-01-01";
$secondDate = "2020-03-04";
$dateDifference = abs(strtotime($secondDate) - strtotime($firstDate));
$years = floor($dateDifference / (365 * 60 * 60 * 24));
$months = floor(($dateDifference - $years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));
$days = floor(($dateDifference - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 *24) / (60 * 60 * 24));
echo $years." year, ".$months." months and ".$days." days";
//output: 1 year, 2 months and 3 days
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