Syntaxe příkazu switch

Příklady kódu

119

pouzdro spínače js

switch(expression) {
  case x:
    // code block
    break;
  case y:
    // code block
    break;
  default:
    // code block
}

příkaz JavaScript switch více případů

//javascript multiple case switch statement
var color = "yellow";
var darkOrLight="";
switch(color) {
    case "yellow":case "pink":case "orange":
        darkOrLight = "Light";
        break;
    case "blue":case "purple":case "brown":
        darkOrLight = "Dark";
        break;
    default:
        darkOrLight = "Unknown";
}

//darkOrLight="Light"

spínač v případě

function whatToDrink(time){
    var drink ;
          switch (time) {
            case "morning":
              drink = "Tea";
              break;
            case "evening":
              drink = "Shake";
              break;
            default:
              drink="Water";   
          }
  	return drink;
}
console.log(whatToDrink("morning")) //Tea
console.log(whatToDrink("evening")) //Shake
console.log(whatToDrink("night"))   //Water
console.log(whatToDrink("daytime")) //Water

spínací pouzdro v

function whatToDrink(time){
    var drink ;
          switch (time) {
            case "morning":
              drink = "Tea";
              break;
            case "evening":
              drink = "Shake";
              break;
            default:
              drink="Water";   
          }
  	return drink;
}
console.log(whatToDrink("morning")) //Tea
console.log(whatToDrink("evening")) //Shake
console.log(whatToDrink("night"))   //Water
console.log(whatToDrink("daytime")) //Water

spínač případě v c

// example of switch case statement
#include <stdio.h>

int main() {
    char operator;
    double n1, n2;

    printf("Enter an operator (+, -, *, /): ");
    scanf("%c", &operator);
    printf("Enter two operands: ");
    scanf("%lf %lf",&n1, &n2);

    switch(operator)
    {
        case '+':
            printf("%.1lf + %.1lf = %.1lf",n1, n2, n1+n2);
            break;

        case '-':
            printf("%.1lf - %.1lf = %.1lf",n1, n2, n1-n2);
            break;

        case '*':
            printf("%.1lf * %.1lf = %.1lf",n1, n2, n1*n2);
            break;

        case '/':
            printf("%.1lf / %.1lf = %.1lf",n1, n2, n1/n2);
            break;

        // operator doesn't match any case constant +, -, *, /
        default:
            printf("Error! operator is not correct");
    }

    return 0;
}

spínací pouzdro v c

// example of switch case statement
#include <stdio.h>

int main() {
    char operator;
    double n1, n2;

    printf("Enter an operator (+, -, *, /): ");
    scanf("%c", &operator);
    printf("Enter two operands: ");
    scanf("%lf %lf",&n1, &n2);

    switch(operator)
    {
        case '+':
            printf("%.1lf + %.1lf = %.1lf",n1, n2, n1+n2);
            break;

        case '-':
            printf("%.1lf - %.1lf = %.1lf",n1, n2, n1-n2);
            break;

        case '*':
            printf("%.1lf * %.1lf = %.1lf",n1, n2, n1*n2);
            break;

        case '/':
            printf("%.1lf / %.1lf = %.1lf",n1, n2, n1/n2);
            break;

        // operator doesn't match any case constant +, -, *, /
        default:
            printf("Error! operator is not correct");
    }

    return 0;
}

prohlášení o přepnutí

int x = Random.Range(0, 5);
switch(x){
case 0:
//preform action if x=0
break;
case 1:
//preform action if x=1
break;
//CONTINUE DOWN
}

funkce spínače

var rand = Math.round(random(1,4));
        
    switch(rand){
        case 1: console.log("Chosen Number : 1");
        break;
        case 2: console.log("Chosen Number : 2");
        break;
        case 3: console.log("Chosen Number : 3");
        break;
        case 4: console.log("Chosen Number : 4");
        default: break;
    }